For a given piece of code, the hit ratio of first cache is 0.1 and the hit ratio of second cache is 0.3. the time required to access the first cache is 10 nanoseconds, the second cache is 100 nanoseconds, and the time to access the underlying physical memory is 1 microsecond, what is the effective memory access time for the piece of code?

effective memory access = 658 ns

Step-by-step explanation:

GIven data:

Effective memory access time is given as

from the data given above we have

hit rate,

access time

Plugging all information in above formula to get the effective memory access

= 1+27+ 630

=658 ns

a) 0.25x times 3. (could be wrong on equation.)

b) 2.25 pound of dark chocolate. (can i eat all the chocolate? plz? anyway, again, could be wrong, but i hope im right. all the chocolate together should be 5.25 pounds)

have a good day!

42

step-by-step explanation: