We wish to construct a 90% confidence interval on the mean of a population known to be normally distributed based on a sample of 20 observations having a sample mean of 8 and a sample standard deviation of 2.
what is the margin of error for this confidence interval?

Margin of error = 0.773

Step-by-step explanation:

We are given the following information in the question.

Sample size, n = 20

Sample mean = 8

Sample standard deviation = 2

90% Confidence interval

Putting the values, we get,  

Margin of error:

Putting the values, we get,  

i assume that by 5 you mean 5 gallons.

(20)(0.25) = 15

removing 15 gallons reduces the tank from 20 to 5.

w'x is 0.

hope it