In a cross between two doubly heterozygous ursa gummi, we observe 461 melting ursa gummi and 39 melting-resistant ursa gummi. if the melting phenotype is the dominant phenotype, make a decision as to whether these data are consistent with the duplicate dominant epistatic mode of inheritance. make your decision based on a significance level threshold of 5%.

Yes they are. chisquare p-value >0.05

Consider the following calculations

Step-by-step explanation:

A codes for melting : aa codes for melting resistance

Bcodes for melting :bb codes for melting resistance

if apunnet squrae is formed on the basis of this it shows the occurrence of duplicate dominance epistasis ratio 15:1

Chi2 values are calculated according to the formula: (Observed Value – Expected Value)2 ÷ (Expected Value)

domain is all the x values included in the

0 ≤ x ≤ 2

range is all the y values of the graph

-2 ≤ y ≤ 2

***keep in mind that there are different ways to show domain and range

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