If you can solve, i will be very impressed.
the area of a rectangle is 108m^2 and its diagonal is 15m. find the perimeter of the rectangle.

42m

Step-by-step explanation:

Given: Area of rectangle= 108

           Diagonal= 15m

Lets assume the value of width of rectangle be `w` and length be `l`.

We know that Area of rectangle=

∴

cross multiplying both side

⇒

∴ w=

Now solving to get value for l and w.

Remember,

⇒

Next substituting the value of w in the equation.

⇒

Opening parenthesis

⇒

Now taking LCD and cross multiplying both side.

⇒

Use quadratic equation to solve.

∴

⇒

Solving it we get two value of l, which is 9 and 12.

We can use any these value of l in substituting.

∴ w=

l= 9m and w= 12m

Now, solving to get perimeter of the rectangle.

perimeter=

⇒ Perimeter=

∴ Perimeter of the rectangle is 42m.

step-by-step explanation:

your answer is -9

step-by-step explanation: