Suppose an experiment is done with criminals released from prison in a certain state where the recidivism rate is 33%: that is, 33% of criminals return to prison three years. one hundred random prisoners are made to attend "boot camp' for two weeks before their release, and it is hoped that "boot camp" will have a effect. suppose 29 of those prisoners return to prison within three years. the null hypothesis is that those attending boot camp have a recidivism rate of 33%. 0.33. complete parts (a) through (c) below. what is p^the sample proportion of successes? (it is somewhat odd to call returning to prison a success). what is p_0 the hypothetical proportion of success under the null hypothesis? what is the value of the test statistic? explain in context. value of the test statistic tells that the observed proportion of prisoners was the null hypothesis proportion of prisoners.

the first one, all those points on the line just make a strait line.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

step-by-step explanation:

there's the chart