In a sample of 12 participants, a researcher estimates the 80% ci for a sample with a mean of m = 22.3 and an estimated standard error (sm) of 4.7. what is the confidence interval at this level of confidence? 80% ci 12.1, 32.5 80% ci 17.6, 27.0 80% ci 15.9, 28.7 there is not enough information to answer this question.

80% CI (15.9, 28.7).

Step-by-step explanation:

We have given that ,

Sample size : n = 12

Confidence interval : 80% = 0.80

Significance level : 1-0.80=0.20

Sample mean :

Estimated standard error : SE = 4.7

Degree of freedom : df = n-1 =11

By t-distribution table , the critical t-value for df = 11 and significance lvel of 0.20 =

Then, the 80% confidence interval will be :

Hence, the correct option is 80% CI (15.9, 28.7).

a. 3/4 ÷ 1/8 = 6

step-by-step explanation:

in the question, the number line represents 3/4 divided into 6 equal units. each arrow represents a unit and there are a total of six arrows.

the size of each unit is 1/8 as shown.

showing that 1/8 divides 3/4 into 6 divisions:

3/4 ÷ 1/8

= 3/4 x 8/1

= 3/1 x 8/4

= 3 x 2

= 6

hence, the number line represents six divisions given by 3/4 ÷ 1/8.