Two truckers leave from the same point driving in opposite directions, the first trucker driving at 62 miles per hour and the second at 66 mph. the first trucker has a one-hour head start. how long, after the first trucker leaves, will they be able to contact each other on their car phones if the phones have a 270-mile range?

1 hour 42 minutes

Step-by-step explanation:

Given: Speed of 1st trucker= 62 mph

           Speed of 2nd trucker= 66 mph

           Total distance need to cover to be in contact is 270 miles

           1st trucker start 1 hour ahead of 2nd trucker

Lets assume 2nd trucker take `x` hours to be in contact and 1st trucker take `(x+1)` hours.

We know, distance=

1st trucker, distance

                     ∴

2nd trucker, distance

                    ∴

Now, putting the values in an equation.

⇒

Opening the parenthesis to solve and subtracting both side by 62

⇒

∴ x= = 1 hour 42 minutes

∴ It will take 1 hour 42 minutes to be able contact each other after first trucker leaves.

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24

2/3

step-by-step explanation: