Two copies of the same hardcover book and 3 copies of the same
paperback book cost $118. sally bought 3 of the hardcover books and
2 of the paperback books for $137. find the cost for each type of book.

Hardcover books cost 35 $ and paperback books cost 16$

Step-by-step explanation:

Lets call h = hardcover books , and p = paperback books

* 2 copies of the hardcover book "h" and 3 copies of the paperback book cost 118

2h + 3p = 118 (equation 1)

* 3 hardcover books and 2 paperback books cost 137

3h+2p=137 (equation 2)

we have two equations, lets  multiply as following

   3 ×(2h + 3p = 118)

(-2) ×(3h + 2p = 137)

6h + 9p = 354

-6h -  4p =-274

0h + 5p = 80                then p=80/5, p=16

from equation 1, if p=40

2h + 3 × (16) = 118

2h + 48        = 118

2h = 118 - 48

2h = 7

h=35

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05