Benjamin & associates, a real estate developer, recently built 195 condominiums in mccall, idaho. the condos were either two-bedroom units or three-bedroom units. if the total number of bedrooms in the entire complex is 497, how many two-bedroom units are there? how many three-bedroom units are there?

There are 88 two bedroom units and 107 three bedroom units.

Step-by-step explanation:

Consider the provided information.

Let x is the number of two-bedroom units and y is the number of three-bedroom units.

Real estate developer, built 195 condominiums in McCall, Idaho.

The total number of bedrooms in the entire complex is 497.

Substitute the value of x in above equation.

Substitute y = 107 in .

Hence, there are 88 two bedroom units and 107 three bedroom units.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

stethere all not eveanp-by-step explanation: