Vector makes three different purchases at three different stores one afternoon. each time he spends 1/3 of the money he is carrying. if he ends the day with $16 how much money did he have at the end of the day?

The money which vector have is $54

Step-by-step explanation:

Given as:

Vector makes three different purchases at three different stores one afternoon. Each time he spends 1/3 of the money he is carrying.

At The end of day vector have money left = $16

Let the money does Vector have at start = $x

Now, According to question

At The first store he had money with him = $x

So, After purchased of item, The money left with him = $x - $ = $

At The second store he had money with him = $

So, After purchased of item, The money left with him = $  - $ = $

At The third store he had money with him = $

So, After purchased of item, The money left with him = $  - $ = $

Now, Again

∵ At The day end the money left with Vector = $16

So, $ = $16

Or. 8 x = $16 × 27

∴ x =

i.e x = $54

So, The money which vector have = x = $54

Hence, The money which vector have is $54 Answer

x+y=90

x=30-y=x

step-by-step explanation:

if you understand you will get the answer