Two planes start from los angeles international airport and fly in opposite directions. the second plane starts 1 2 hour after the first plane, but its speed is 100 kilometers per hour faster. find the speed of each plane when 2 hours after the first plane departs the planes are 2985 kilometers apart. a) the first plane that leaves the airport travels at kilometers per hour.
b) the second plane that leaves the airport travels at kilometers per hour.

A) The first plane that leaves the airport travels at 810 kilometers per hour.

B) The second plane that leaves the airport travels at 910 kilometers per hour.

Step-by-step explanation:

Consider the provided information.

The second plane starts 1/2 hour after the first plane, but its speed is 100 kilometers per hour faster.

Let the speed of the first plane is x km/hr.

The speed of second plane is x+100 km/hr.

The first plane fly for 2 hr and the second plane fly for 1.5 hr. Because second plane starts 1/2 hour after the first plane,

As we know: distance = speed × time

Total distance cover by both planes is:

Therefore, the speed of first plane is 810 km/hr.

The speed of second plane is 810 + 100 = 910 km/hr

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.