Thomas needs 8876 bricks to build house a. he needs 3975 more bricks to build house b than house a. how many bricks does he need altogether to build the two houses?

Thomas needs 21,727 bricks altogether to build both houses.

Step-by-step explanation:

House A requires: 8,876 bricks

House B requires: 8,876 + 3975 = 12,851 bricks

8,876 bricks + 12,851 bricks = 21,727 bricks

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752