Based on historical data, the diameter of a ball bearing is normally distributed with a mean of 0.527 cm and a standard deviation of 0.008 cm. suppose that a sample of 18 ball bearings are randomly selected from a very large lot. determine the probability that the average diameter of a sampled ball bearing is greater than 0.530 cm.

0.056 is the probability that average diameter of a sampled ball bearing is greater than 0.530 cm.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0.527 cm

Standard Deviation, σ = 0.008 cm

Sample size, n = 18

We are given that the distribution of diameter of a ball bearing is a bell shaped distribution that is a normal distribution.

Formula:  

P(average diameter of a sampled ball bearing is greater than 0.530 cm)  

P(x > 0.530)  

Calculation the value from standard normal z table, we have,  

Thus, 0.056 is the probability that average diameter of a sampled ball bearing is greater than 0.530 cm.

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft

my guess is

step-by-step explanation: