Alarge cooperation has quality control over its fertilizers. the fertilizes are composed of nitrogen. the fertilizer requires 3 mg of nitrogen. the distribution of the percentage of nitrogen is unknown with a mean of 2.5 mg and a standard deviation of 0.1. a specialist randomly checked 100 fertilizer samples. what is the probability that the mean of the sample of 100 fertilizers less than 2 mg?

It is impossible that the mean of the sample of 100 fertilizers less than 2 mg.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.5 mg

Standard Deviation, σ = 0.1 mg

We are given that the distribution of percentage of nitrogen score is unknown.

Formula with sampling:

P( mean of the sample of 100 fertilizers less than 2 mg)  

P(x < 2)  

Calculation the value from standard normal z table, we have,  

Thus, it is impossible that the mean of the sample of 100 fertilizers less than 2 mg.

did you get the answer yet?

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.