Suppose that a large pumpkin empty a swimming pool in 40 hours and that a small pumpkin empty a pool and 70 hours working together how long will it take to empty the pool

Total 25.45 hours will be taken to empty the pool.

Step-by-step explanation:

Time taken by large pumpkin to empty the pool=40 hours

Time taken by the smaller pumpkins to empty the pool=70 hours

Amount of pool emptied by large pumpkin in one hour=

Amount of pool emptied by small pumpkin in one hour=

Amount of pool emptied in one hour if both pumpkins work together=

+

=

Therefore, the no. of days will be the reciprocal of the amount of work done in one hour ie .

Total 25.45 hours will be taken to empty the pool.

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option