Atriangular piece of land has one of its angle equal to 90°.the area of this land is 330sq m. if one side adjacent to the right angle is 11m what are the lengths of the other two sides

  60 m, 61 m

Step-by-step explanation:

If "a" and "b" represent the lengths of the sides adjacent to the right angle, the area is ...

  area = (1/2)ab

Filling in the given information, we can find the other side to be ...

  330 m² = (1/2)(11 m)b

  60 m = b  . . . . . . divide by the coefficient of b

Then the remaining side can be found from the Pythagorean theorem:

  c² = a² + b² = 11²  + 60² = 3721

  c = √3721 = 61 . . . meters

The lengths of the other two sides are 60 m and 61 m.

false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.