Suppose we have a binomial experiment with n= 40 trials and a probability of success p= 0.50.is it appropriate to use a normal approximation normal distribution? why? compute µ and of the approximation normal distribution. use a continuity correction factor to convert the statement r≥23 successes to a statement about the corresponding normal variable x. estimate p(r≥23)is it unusual for a binomial experiment with 40 trials and probability of success to 0.50 to have a 23 or more successes? explain.

We can approximate to normal.

The parameters of the approximate normal distribution are:

It is not unusual to have 23 or more successes. The probabiltity of this event happening is 13.4%.

Step-by-step explanation:

To approximate the binomial distribution to a normal distribution, we can calculate n*p and n*q and if both are bigger than 5 we can do the approximation.

We can approximate to normal.

The parameters of the approximate normal distribution are:

The continuity correction factor is used because the binomial is a discrete function and the normal a continous function.

The probability of 23 successes must be expressed in the normal distribution as:

It is not unusual to have 23 or more successes. The probabiltity of this event happening is 13.4%.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.