Your drawer contains 6 gold earrings and 7 silver earrings. you randomly choose an earring. without replacing the first, you choose a second earring. what is the probability that both earrings are silver

The probability that both earrings are silver is 0.27.

Step-by-step explanation:

Basically, we have to pick in a such a way that the first earring is a silver earring and the second one is also a silver earring.

Constituents of the box= 7 silver, 6 gold.

Probability=

Therefore, probability of picking up a silver earring in the first attempt(A)=  

As we have picked up, one earring from the bag, the no. of silver earrings have been decreased by 1 as have the total no. of earrings.

Therefore, the total no. of earrings now=12

No. of silver earrings in the bag now=6

Probability of picking up a silver in the second attempt after the above first attempt(B)=

P(A∩B)=P(A)*P(B)

            = x

             =

              =0.269

The probability that both earrings are silver is 0.27.

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3