If the graph of function gis 6 units below the graph of function f, which could be function g?
rx) = -2x +7

o a. g(x) = -6x + 7
ob. 8x) = -2x + 1
oc. x) =-2x + 20
d. g(x) = -2x - 6

B.

Step-by-step explanation:

Given:

The given function is:

The graph of another function 'g' is 6 units below the graph of the given function 'f'.

In other words, we can say that the graph of function 'g' is the transformation of function 'f' and the transformation is a translation by 6 units down as the graph of is below the graph of

Thus, as per the rules of transformation,

If a graph is shifted down by 'C' units where 'C' is a positive number, then the function rule is given as:

Here,

Therefore, the equation of is given as:

So, the option B is the correct answer.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0