What is the equation of the line that passes through the points (3,-2) and (6,3)? put your answer in full reduced form

Step-by-step explanation:

From the coordinate geometry, equation of line that passes through two coordinates will be

y-y1 ={(y2-y1)/x2-x1)}(x-x2) where x1=3,y1= -2, x2 =6, y2 = 3. therefore substitute for the values

y-(-2) ={ 3-(-2)/6-3} x (x-6)

y+2 = 3+2/3 x (x-6)

y+2 =5/3(x-6) multiply both side by 3,

3(y+2) = 5(x-6)

3y+6 =5x-30

3y = 5x -30 -6

3y = 5x - 36. Therefore the equation of the line is

3y = 5x - 36.

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.