Afarmer wants to test the effectiveness of a pest control method in allowing strawberry blooms to yield marketable strawberries. of a random sample of 100 blooms, 77 yield marketable strawberries. is this evidence that two thirds or more of all blooms grown with this pest control method end up as marketable strawberries? the value of the z statistic for this test is about?

a. z = 2.46
b. z = 1.03
c. z = 2.19

Option C is right.

Step-by-step explanation:

Given that a  farmer wants to test the effectiveness of a pest control method in allowing strawberry blooms to yield marketable strawberries.

Samplesize = 100

Favorable =77

Sample proportion p = 0.77

(Right tailed test)

Assuming H0 to be true,

Standard error of proportion p =

p difference = 0.103

Test statistic Z = p difference/std error = 2.186

=2.19

Option C is right

< 6 cm to > 26 cm i believe

step-by-step explanation:

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.