Arectangle with are 315 square inches has a length that is one less than four times the width. find the length and the width of the rectangle

l=35 inches

w= 9 inches

Step-by-step explanation:

Area is 315 square inches

Area=l*w=315     (Equation 1)

l=4w-1    (Equation 2)

Putting value of l from equation 2 in equation 1

(4w-1)w=315

4w^2-w-315=0

Solving by using quadratic equation

a=4, b=-1, c=-315

w= (-b+sqrt(b^2-4ac))/2a    and   w= (-b-sqrt(b^2-4ac))/2a

w= (1+sqrt(1+5040))/8         and    w= (1-sqrt(1+5040))/8

w= (1+sqrt(5041))/8             and    w= (1-sqrt(5041))/8

sqrt(5041)=71

w= (1+71)/8             and    w= (1-71)/8

w=72/8                  and     w=-70/8

as width can't be a negative number so we'll solve for w=72/8=9

width =9 inches

putting w in equation 2

l=(4*9)-1

l=35 inches

translate k to n and reflect across the line containing jk.

step-by-step explanation:

the ratio of red paint to blue paint is always 9/7. that means that, whatever x's value, (4x+12)/(4x-4) has that same ratio. so, set up an equation and cross-multiply to solve for x:

9/7 = (4x+12)/(4x-4)

9(4x-4) = 7(4x+12)

36x - 36 = 28x + 84

8x - 36 = 84

8x = 120

x = 15