Agun shop sells gunpowder. monthly demand for gunpowder is normally distributed, averages 20 pounds, and has a standard deviation of 2 pounds. the shop manager wishesto stock gunpowder inventory at the beginning of each month so that there is only a 2%chance that the shop will run out of gunpowder (i. e., that demand will exceed inventory)in any given month. calculate the amount of gunpowder to stock in inventory, in pounds.
(a) 16(b) 23(c) 24(d) 32(e) 43

Option (C) 24

Step-by-step explanation:

Let the random variable denoting the amount of gunpowder in the shop be 'x'.

x ~ N(20, 2) i.e. (x-20)/2 ~ (0, 1)

Let 'a' be the amount (in pounds) of gunpowder to stock in inventory.

Thus, P(x<a) = 1 - 0.02 = 0.98

i.e. P[(x-20)/2<(a-20)/2] = 0.98

i.e. ф [(a-2)/2] = 0.98

i.e. (a-20)/2 = ф⁻¹ (0.98) = 2.054

i.e. a = 20 + (2 × 2.054) = 24.108 ≈ 24 pounds

24 pounds of gunpowder to stock in inventory.

Option (C) 24

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: