In a game you flip a coin twice, and record the number of heads that occur. you get 10 points for 2 heads, zero points for 1 head, and 5 points for no heads. what is the expected value for the number of points you’ll win per turn?

Step-by-step explanation:

P(2 heads) = P(first flip = head)*P(second flip = head)

=> =

P(1 head) = P(first flip = head)*P(second flip = tail) + P(first flip = tail)*P(second flip = head)

=

P(no heads) = P(first flip = tail)*P(second flip = tail)

=

E(winning) =

=

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