Graph the equation by plotting three
points. if all three are correct, the line
will appear.
-2y = -x + 8

The three points for the line  -2y = -x + 8 are

point A( x₁ , y₁) ≡ ( 0 ,-4)

point B( x₂ , y₂) ≡ (8 , 0)

point C(x₃ , y₃ ) ≡ (2 , -3)

The Graph is attached below.

Step-by-step explanation:

Given:

-2y = -x + 8........... equation of a line

Let the points be point A, and point B  

To Find:

point A( x₁ , y₁) ≡  ?

point B( x₂ , y₂) ≡ ?

point C(x₃ , y₃ ) ≡ ?

Solution:

For Drawing a graph we require minimum two points but we will have here three points.

For point A( x₁ , y₁)

Put x = 0 in the given equation we get

-2y = -x + 8

-2y = 0 + 8

∴

∴ point A( x₁ , y₁) ≡ ( 0 ,-4)

For point B( x₂ , y₂)

Put y= 0 in the given equation we get

-2 × 0 = -x + 8

x =  8

∴ point B( x₂ , y₂)  ≡ (8 , 0)

For point C(x₃ , y₃ )

Put x = 2 in the given equation we get  

-2y = -2 + 8

-2y = 6

y = - 3

∴ point C(x₃ , y₃ )≡ (2 , -3)

Therefore,

The three points for the line  -2y = -x + 8 are

point A( x₁ , y₁) ≡ ( 0 ,-4) (blue color point on the graph)

point B( x₂ , y₂) ≡ (8 , 0) (green color point on the graph)

point C(x₃ , y₃ ) ≡ (2 , -3) (purple color point on the graph)

The Graph is attached below..

  answer:

  write 548 as 500 + 40 + 8. multiply each addend by 5. then add the three products to get 2,740.

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.