Nan compos-mentis, a technical consultant, claims that she can increase average hourly productivity for the fabricators at stryker manufacturing by more than 10 units per worker. to support her claim, nan plans to select a sample of workers, provide the workers in the sample with special training, and then use results from the sample in a hypothesis test designed to establish whether the training has had the desired effect. what null and alternative hypotheses would you recommend here?

Step-by-step explanation:

given that Nan Compos-Mentis, a technical consultant, claims that she can increase average hourly productivity for the fabricators at Stryker Manufacturing by more than 10 units per worker.

To support her claim, Nan plans to select a sample of workers, provide the workers in the sample with special training, and then use results from the sample in a hypothesis test designed to establish whether the training has had the desired effect.

Here her matter of interest is whether training improves the mean score of hourly productivity

Hence the hypotheses should be

A right tailed test.

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

question 1: step-by-step explanation:

1/4 of 84 = 84÷4= 21