The null and alternate hypotheses are:

h0: μ1 ≤ μ2
h1: μ1 > μ2
a random sample of 29 items from the first population showed a mean of 112 and a standard deviation of 9. a sample of 15 items for the second population showed a mean of 97 and a standard deviation of 12. use the 0.10 significant level.
a. find the degrees of freedom for unequal variance test. (round down your answer to the nearest whole number.)
b) state the decision rule for 0.100 significance level. (round your answer to 3 decimal places.)
reject h0 if t >
c) compute the value of the test statistic
d) what is your decision regarding the null hypothesis? use the 0.10 significance level.

Step-by-step explanation:

Given that the  null and alternate hypotheses are:

H0: μ1 ≤ μ2

H1: μ1 > μ2

Group   Group One     Group Two  

Mean112.0097.00

SD9.0012.00

SEM1.673.10

N29    15    

The mean of Group One minus Group Two equals 15.00

a) df = 42

 standard error of difference = 3.212

 b) Reject H0 if t statistic >1.302

  t = 4.6699

 Since t > 1.302, we reject null hypothesis

It is evident that the mean I is greater than mean 2.

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

80 the answer is 80

step-by-step explanation: