What is an equation of the line that passes through the point (-7,-8) and is parallel to the line 2x-y=6

The equation of line Passing through point ( - 7 , - 8 ) and is parallel to given line 2 x - y = 6  is  y = 2 x + 6

Step-by-step explanation:

Given equation of line as :

2 x - y = 6

or,  y = 2 x - 6

∵ Standard equation of line is give as

y = m x + c

Where m is the slope of line and c is the y-intercept

Now, comparing given line equation with standard eq

So, The slope of the given line = m = 2

Again,

The other line if passing through the points (- 7 , - 8 ) And  is parallel to given line

So, for parallel lines condition , the slope of both lines are equal

Let The slope of other line = M

So,  M = m = 2

∴ The equation of line with slope M and passing through points ( -7 , - 8) is

y = M x + c

Now , satisfying the points

So, - 8 = 2 × ( - 7 ) + c

or, - 8 = - 14  + c

Or, - 8 + 14 =  c

∴  c = 6

So, The equation of line with slope 2  and passing through points ( -7 , - 8 )

y =  2 x + 6

Hence The equation of line Passing through point ( - 7 , - 8 ) and is parallel to given line 2 x - y = 6 is  y = 2 x + 6   Answer

correct

step-by-step explanation: