Below is a two-column proof incorrectly proving that the three angles of δpqr sum to 180°: statements reasons draw line zy parallel to segment pq construction m∠zrp + m∠prq + m∠qry = m∠zry angle addition postulate ∠zrp ≅ ∠rpq alternate interior angles theorem ∠qry ≅ ∠pqr alternate interior angles theorem m∠rpq + m∠prq + m∠pqr = m∠zry substitution m∠zry = 180° definition of a straight angle m∠rpq + m∠prq + m∠pqr = 180° additive property of equality which statement will accurately correct the two-column proof?

Proof with statement is below.

Step-by-step explanation:

To Prove:

m∠RPQ + m∠PRQ + m∠PQR = 180°

Proof:

Draw line ZY parallel to segment PQ ............{Construction}

1. m∠ZRP + m∠PRQ + m∠QRY = m∠ZRY  .....{Angle Addition Postulate}

2. ∠ZRP ≅ ∠RPQ   ........{Alternate angles equal as ZY || PQ}

3. ∠QRY ≅ ∠PQR  .........{Alternate angles equal as ZY || PQ}

4. m∠RPQ + m∠PRQ + m∠PQR = m∠ZRY  ....{The three angles of ΔPQR equal 180° according to Substitution }

5. m∠ZRY = 180°   ......{Definition of a Straight Angle}

6. m∠RPQ + m∠PRQ + m∠PQR = 180° ...{Additive Property of Equality}...............PROVED

c

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.