Aperson stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters per second.
at a certain instant, the car is 24 meters from the intersection.
what is the rate of change of the distance between the car and the person at that instant (in meters per second)?

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

answer is b

step-by-step explanation:

this is a good question! i'll do some research and come back when i have the answer!