Supply rebuttals to the following complaints about the proof of theorem 1.5.1.
(a) every rational numbers has a decimal expansion so we could apply this same argument to show that the set of rational numbers between 0 and 1 is un- countable. however, because we know that any subset of q must be countable, the proof of theorem 1.5.1 must be flawed.
(b) a few numbers have two different decimal representations. specifically, any decimal expansion that terminates can also be written with repeating 9's. for instance, 1/2 can be written as .5 or as . doesn't this cause some problems?

the number of the people going.

step-by-step explanation:

the cost to buy one movie ticket is $7. if the total cost for the movie is a function of how many people go, then the input is : the number of the people going.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

you divide them and then you get the answer i took this class this year

step-by-step explanation: