Mathematics, 12.12.2019 22:31 ritahastie2896

Work out the equation of the line which passes through the point (-1, 2) and is parallel to the line y=x+4

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Answer from: nvc1127

The equation of line for point (-1,2) can be determine by general equation of line.

The equation of line for point (-1,2) is y=x+3 .

Given:

The line is parallel to line y=x+4 .

The line passes through the point (-1,2) .

Write the general equation for line.

y=mx+c -------------------------- (1)

Here, is slope and is y-intercept.

Write the given line equation.

y=x+4 -----------------------------(2)

On comparing equation (1) and (2) we get,

$m=1\\c=4$

As per the definition of line, parallel line has equal slope.

Substitute m=1 , x=-1 and y=2 for the given point (-1,2) in equation (1).

2 = 1(-1) + c2 = -1 + cc = 3

Write the equation of line from the above value.

$y=1\times x+3\\y=x+3$

Thus, the equation of line for point (-1,2) is y=x+3 .

Learn more about line equation here:

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Answer from: nikolas36

The equation of the line which passes through the point (-1, 2) and is parallel to the line y = x + 4 is y = x + 3

Solution:

Gtiven that line passes through the point (-1, 2) and parallel to line y = x + 4

We have to find the equation of line

The equation of line in slope intercept form is given as:

y = mx + c eqn 1

where "m" is the slope of line and "c" is the y - intercept

Let us first find the slope of line

Given equation of line is y = x + 4

On comparing the given equation of line y = x + 4 with general slope intercept form y = mx + c,

we get slope of line "m" = 1

We know that slopes of parallel lines are equal

So the slope of line parallel to line having equation y = x + 4 is also 1

Now we have to find the equation of line having slope "m" = 1 and passes through point (-1, 2)

Substitute m = 1 and (x, y) = (-1, 2) in eqn 1

2 = 1(-1) + c

2 = -1 + c

c = 3

Thus the required equation of line is:

Substitute c = 3 and m = 1 in eqn 1

y = 1x + 3

y = x + 3

Thus the required equation of line is found out

Answer from: Quest

my nutterbutter

Answer from: Quest

see explanation

step-by-step explanation:

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

remove brackets and collect like terms

13 - $\frac{3}{2}$ r - 1 + r

= 12 - $\frac{1}{2}$ r

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

remove brackets and collect like terms

= 7r - $\frac{3}{2}$ - $\frac{2}{3}$ - 6r

[- $\frac{3}{2}$ - $\frac{2}{3}$ = - $\frac{9}{6}$ - $\frac{4}{6}$ = - $\frac{13}{6}$ ]

= r - $\frac{13}{6}$

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Work out the equation of the line which passes through the point (-1, 2) and is parallel to the line...

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