Given the directrix of y = −1 and focus of (0, 3), which is the equation of the parabola? y = one eighthx2 − 1 y = −one eighthx2 + 1 y = one eighthx2 + 1 y = −one eighthx2 − 1

Step-by-step explanation:

we know that

The standard form of a quadratic equation is

where

(h,k) is the vertex

(h, k+p) is the focus

y=k-p is the directrix

we have

focus (0,3)

so

> equation A

directrix y=-1

so

---> equation B

Adds equation A and equation B

Find the value of p

substitute the values in the equation

therefore

y = one eighthx2 + 1

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y