Which polynomial is prime x^3+3x^2+2x+6

Step-by-step explanation:

Prime numbers have only one factor pair, the number itself and 1. Some polynomials can be factored and some cannot be so a polynomial is a prime polynomial if it can't be factored into the standard linear form of (x+a)((x+b).

For the given polynomial x^3+3x^2+2x+6

Re-arranging the Polynomial to find out whether it could be factored or not

x^3+2x+3x^2+6=0

x(x^2+2) +3 (x^2+2)=0

(x+3)(x^2+2)=0

x+3=0 and x^2+2=0

x=-3, x^2= -2

x=-3, x=sqrt(-2), x= -sqrt(-2)

As the polynomial is factorable it is not prime

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!