The probability that latisha orders french fries at lunch is .32 and the probability that she orders a grilled cheese and fries is .65. if the probability that she orders just a grilled cheese sandwich is .76, what is the probability that she will order a grilled cheese and fries?

There is a typo error in the last part of the question. The corrected part is-

"If the probability that she orders just a grilled cheese sandwich is .76, what is the probability that she will order a grilled cheese or fries?"

The probability that she will order a grilled cheese sandwich or fries is 0.43.

Step-by-step explanation:

Given:

Probability of ordering fries is,

Probability of ordering cheese sandwich is,

Probability of ordering both sandwich and fries is,

Probability of ordering cheese sandwich or fries is given by the union of both the events 'F' and 'S' given as .

Now, using addition theorem of probability, we get:

Therefore, probability of ordering cheese sandwich or fries is 0.43.

33

step-by-step explanation: g=6

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0