5x + 3y = -2
3x + 2y = -1
solve the system of equations.
a) (-1, 1)
b) (1, -1)
c) (-1, -2)
d) (1/3, 1)

x = -1 , y = 1

Step-by-step explanation:

Solve the following system:

{5 x + 3 y = -2 | (equation 1)

3 x + 2 y = -1 | (equation 2)

Subtract 3/5 × (equation 1) from equation 2:

{5 x + 3 y = -2 | (equation 1)

0 x+y/5 = 1/5 | (equation 2)

Multiply equation 2 by 5:

{5 x + 3 y = -2 | (equation 1)

0 x+y = 1 | (equation 2)

Subtract 3 × (equation 2) from equation 1:

{5 x+0 y = -5 | (equation 1)

0 x+y = 1 | (equation 2)

Divide equation 1 by 5:

{x+0 y = -1 | (equation 1)

0 x+y = 1 | (equation 2)

Collect results:

{x = -1 , y = 1

ask the math teacher she or he would know lol.

step-by-step explanation: