From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.69 with a population standard deviation of 3.23. what is the 95% confidence interval for the amount of time spent on administrative issues?

(20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

, where = sample mean.

z*= critical z-value

n= sample size.

= Population standard deviation.

By considering the given question , we have

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.

add a pic of the graph, then ill edit this "answer" and solve it for you : 3

step-by-step explanation: