Asphere has a radius of 4 inches. what is the surface area of the smallest cube that could circumscribe the sphere?

Step-by-step explanation:

we know that

The smallest cube that could circumscribe the sphere has a length side equal to the diameter of the sphere

In this problem

The radius of the sphere is

The diameter of the sphere is two times the radius

so

The length side of the cube is

Remember that

The surface area of a cube is equal to the area of its six faces

so

substitute the value of b

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

lol

step-by-step explanation: