6. e1 and e2 are events from the same sample space; p(e1)=0.37, p(e2)=0.45, and p(e1, e2)=0.14. a. find the probability that e2 does not occur. b. find the probability that either e1 or e2 occurs. c. find the probability that neither e1 nor e2 occurs.

a. 0.55

b. 0.68

c. 0.18

Step-by-step explanation:

a. The probability that E2 does not occur is one minus the probability that E2 occurs:

b. The probability that either E1 or E2 occurs is given by the sum of their individual probabilities minus their joint probability:

c. The probability that neither E1 nor E2 occurs is one minus the probability of E1 occurring minus the probability of E2 occurring:

17

step-by-step explanation:

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

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