What is the substitution equation for 7x-2y=35 and x-4y=5

y=0 and x=5

Step-by-step explanation:

multiplying equation 2 by 7 and subtracting it from equation 1 we get

7x-2y=35 - 7x-28y=35

26y=0

y= 0/26

y = 0

putting value of y in equation 1

7x -2(0) = 35

7x - 0 = 35

7x = 35

x = 35/7

x = 5

i need the options

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3