Line cd passes through points c(3, –5) and d(6, 0). what is the equation of line cd in standard form?

To answer the problem above, we can start with the formation of the point-slope form of a line. The slope is solved through,

                                    m = (y2 - y1)/(x2 - x1)
                                     m = (0 - -5)/ (6 - 3) = 5/3

The point - slope form of the equation of the line is,

                                    y - y2 = m(x - x2)

Substituting the known data, 

                                   y - 0 = (5/3)(x - 6)
This simplifies into, 

                                    y = 5x/3 - 10

Thus, the standard form of the equation is, 

                                      5x - 3y = 30

The answer to your question is 1/9