F(x)=
\,\,3x^2-6x+5
3x
2
−6x+5
g(x)=
g(x)=
\,\,-4x-13
−4x−13
\text{find: }f\circ g(x)
find: f∘g(x)

The function in the form of fog(x) is written as  48 x² + 336 x +  590

Step-by-step explanation:

Given function as :

f(x) = 3 x² - 6 x + 5

g(x) = - 4 x - 13

So, The function in the form of fog(x) is written as

We, substitute the value of g(x) into f(x)

∴ fog(x) = 3 (g(x))² - 6 (g(x)) + 5

Or, fog(x) = 3 (- 4 x - 13 )² - 6 ( - 4 x - 13 ) + 5

or,  fog(x) = 3 (16 x² + 169 + 104 x) + 24 x + 78 + 5

or , fog(x) = 48 x² + 507 + 312 x + 24 x + 78 + 5

or , fog(x) = 48 x² + 336 x +  590

So, The function in the form of fog(x) = 48 x² + 336 x +  590

Hence The function in the form of fog(x) is written as  48 x² + 336 x +  590 Answer

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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