Gail needs to earn a upper b in her geology class. her current test scores are 82 comma 76 comma 94 comma and 86. her final exam is worth 6 test scores. in order to earn a upper b, gail's average must lie between 80 and 89 inclusive. what range of scores can gail receive on the final exam to earn a upper b in the course?

  [77, 92]

Step-by-step explanation:

Gail wants her average to lie between 80 and 89, so she must have a test score T that satisfies ...

  80 ≤ (82 +76 +94 +86 +6T)/(10) ≤ 89

  80 ≤ 33.8 +0.6T ≤ 89 . . . . . . simplify

  46.2 ≤ 0.6T ≤ 55.2 . . . . . . . . subtract 33.8

  77 ≤ T ≤ 92 . . . . . . . . . . . . . . . divide by 0.6

Gail must receive between 77 and 92 (inclusive) on her final to earn a B in the course.

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

(a) common ratio in the given sequence is, 3

(b) push ups will do kendall do on the 20th week

step-by-step explanation:

geometric sequence is a sequence of numbers that follows a pattern were the next term is found by multiplying by a constant called the common ratio(r)

(a)

given the sequence: 6 , 18 , 54 , 162 ,

this sequence is geometric sequence where each term is 3 times the previous term.

therefore,

common ratio(r) = 3.

(b)

a formula for nth term of geometric sequence is given by;

,   where r is the common ratio between the successive terms and is the first term,

to find how many push ups will kendall do on the 20th week.

here. n = 20th term.

in the given sequence first term

then;

simplify:

therefore, push ups will do kendall do on the 20th week