Xf(x) = βx2 + x + 6
β2 a
β1 4
0 b
1 6
2 c
a = b = c =...
Mathematics, 10.12.2019 21:31 anthonylopez1
Xf(x) = βx2 + x + 6
β2 a
β1 4
0 b
1 6
2 c
a = b = c =
Answers: 1
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