Aresearcher wants to know if the average time in jail for robbery has increased from what it was several years ago when the average sentence was 7 years.
he obtains data on 400 more recent robberies and finds an average time served of 7.5 years.

if we assume the standard deviation is 3 years, what is the p-value of the test?

P-value of the test is 0.000434

Step-by-step explanation:

: average time in jail for robbery is same as it was several years ago

: average time in jail for robbery has increased from what it was several years ago

Test statistic can be calculated using

z= where

Then z= ≈3.33

Corresponding one tailed p-value of the test is 0.000434

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²