Mathematics, 10.12.2019 02:31 bookworm43

What is the slope of a line perpendicular to a line whose equation is -4x - 2y + 18 =0 ?

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Answer from: jasonoliva13

Slope of a line perpendicular to a line whose equation is -4x - 2y + 18 = 0 is $\frac{1}{2}$

Solution:

Given that the line equation is -4x - 2y + 18 = 0

We have to find the slope of line perpendicular to the above line equation

Let us first find the slope of given line

The slope intercept form of a line is given as:

y = mx + c

where "m" is the slope of line and "c" is the y - intercept

Given equation of line is:

-4x - 2y + 18 = 0

Let us rearrange the above equation into slope intercept form

2y = -4x + 18

y = -2x + 9

Comparing y = -2x + 9 with general slope intercept form y = mx + c, we get,

m = -2

Thus the slope of give line equation is -2

Now we have to find the slope of line which is perpendicular to given line having equation -4x - 2y + 18 = 0 and slope -2

Since the lines are perpendicular, product of slopes of both lines is equal to -1

Slope of line perpendicular to given line x slope of given line = -1

Slope of line perpendicular to given line x -2 = -1

Slope of line perpendicular to given line = $\frac{1}{2}$

Thus slope of a line perpendicular to a line whose equation is -4x - 2y + 18 =0 is $\frac{1}{2}$

Answer from: Quest

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a

Answer from: Quest

answer:

total cost for tiles and paints is $924.

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

$\text{area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)$

$\text{area of walls and ceiling}=1200+90+120$

$\text{area of walls and ceiling}=1410$

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

$\text{ the total painting cost}=10*(\frac{1410}{25})$

$\text{ the total painting cost}=10*56.4=564$

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

$\text{area of floor} = 40*3\text{ square meters}$

$\text{area of floor} =120\text{ square meters}$

given: 1m squared floor tiles costs $3. so,

$\text{total cost for tiles} = 3*120 = 360$

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

$\text{combined total cost}= 564+360 = 924$

therefore, the combined total cost of tiles and paint is $924.

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