Which function in vertex form is equivalent to f(x) = x2 + x +1? f(x) = (x + one-quarter) squared + three-quarters f(x) = (x + one-quarter) squared + five-quarters f(x) = (x + one-half) squared + three-quarters f(x) = (x + one-half) squared + five-quarters

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

x² + x + 1 ← to obtain vertex form use metod of completing the square

To complete the square

add/ subtract (half the coefficient of the x- term )² to x² + x

x² + 2()x + - + 1

f(x) = (x + )² + ← in vertex form

answer: the answer is fre sha voca do

step-by-step explanation:

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !