Ab = 3x
dc = x + 4
ad = y + 2
bc = 2y

quadrilateral abcd is a parallelogram if both pairs of opposite sides are congruent. show that quadrilateral abcd is a parallelogram by finding the lengths of the opposite side pairs.

see explanation

Step-by-step explanation:

If a parallelogram then AB = DC and AD = BC

Equating AB = DC, then

3x = x + 4 ( subtract x from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

Thus

AB = 3x = 3(2) = 6 and DC = x + 4 = 2 + 4 = 6 ⇒ AB = DC

Equating AD and BC, then

2y = y + 2 ( subtract y from both sides )

y = 2

Thus AD = y + 2 = 2 + 2 = 4 and BC = 2y = 2(2) = 4 ⇒ AD = BC

Since opposite sides are congruent then ABCD is a parallelogram

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

europa2433

europa2433

step-by-step explanation: