Margaret drove to a business appointment at 60 mph. her average speed on the return trip was 50 mph. the return trip took one fifth 1 5 hr longer because of heavy traffic. how far did she travel to the appointment?

Step-by-step explanation:

Let the distance to appoint be s and time for appointment trip be t.

The return trip took one fifth hr longer because of heavy traffic.

Time for return trip = t + one fifth hour = (t + 0.2) hr

Speed of appointment trip = 60 mph

Speed of return trip = 50 mph

We have

                  s = 60 t     and

                  s = 50 (t + 0.2)

                   s = 50 t + 10

                   60t = 50 t + 10

                     10 t = 10

                       t = 1 hour

Distance to appointment = 60 t = 60 x 1 = 60 miles

She traveled 60 miles to the appointment place.  

use formula for the circle a=3.14

step-by-step explanation: