What is the equation of the line which includes points (-3, 2) and (1, 6)?
o
y = x - 5
o y = x + 5
ov=+6
ov=-4x+6

required equation of line is y=x+5

Step-by-step explanation:

equation of line passing through points and

=\times{x-x_1}

put the co-ordinate (-3,2) and(1,6)

y-2=\times{x+3}

y-2=x+3

y=x+5 answer

b and c

step-by-step explanation:

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2